(\boxed4464)
Triangle BEF: vertices B(8,0), E(3,15), F(24/11, 120/11). Use shoelace formula: Area = 1/2 | x1(y2-y3) + x2(y3-y1) + x3(y1-y2) | = 1/2 | 8(15 - 120/11) + 3(120/11 - 0) + (24/11)(0 - 15) | = 1/2 | 8( (165-120)/11 ) + 3(120/11) + (24/11)(-15) | = 1/2 | 8*(45/11) + 360/11 - 360/11 | = 1/2 | 360/11 | = 180/11. Mathcounts National Sprint Round Problems And Solutions
(\fraca+bab = \frac317 \Rightarrow 17(a+b) = 3ab). Solve for one variable: (17a + 17b = 3ab \Rightarrow 17a = 3ab - 17b = b(3a - 17) \Rightarrow b = \frac17a3a-17). Solve for one variable: (17a + 17b =
Line AE: from A(0,0) to E(3,15): slope = 15/3=5, equation y=5x. Line BD: from B(8,0) to D(0,15): slope = (15-0)/(0-8) = -15/8, equation: y = (-15/8)(x-8) = (-15/8)x + 15. 0) to E(3